What are the solutions to the equation 0=2(x-3)^2-6 ?

The solutions to the equation 0=2(x-3)^2-6 are x=sqrt(3)+3,x=-sqrt(3)+3

Find the zeros of 0=2(x-3)^2-6

The zeros of 0=2(x-3)^2-6 are x=sqrt(3)+3,x=-sqrt(3)+3

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0 = 2 (x - 3)^{2} - 6

x = 3 + 3, x = - 3 + 3

Decimal Notation

x = 4.73205 \dots, x = 1.26794 \dots

Solution steps

0 = 2 (x - 3)^{2} - 6

Switch sides

2 (x - 3)^{2} - 6 = 0

Move

6

to the right side

2 (x - 3)^{2} = 6

Divide both sides by

2

(x - 3)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 3 : x = 3 + 3

Solve

x - 3 = - 3 : x = - 3 + 3

The solutions to the quadratic equation are:

x = 3 + 3, x = - 3 + 3

2 x^{2} - 5 = - 7

2 x^{2} - 4 x - 5 = 2 x + x^{2} - 10

5 x^{2} - 14 x + 14 = 0

6 m (m + 4) = m - 15

(2 x - 3)^{2} = 2 x - x^{2}

What are the solutions to the equation 0=2(x-3)^2-6 ?
The solutions to the equation 0=2(x-3)^2-6 are x=sqrt(3)+3,x=-sqrt(3)+3
Find the zeros of 0=2(x-3)^2-6
The zeros of 0=2(x-3)^2-6 are x=sqrt(3)+3,x=-sqrt(3)+3