What are the solutions to the equation -3x^2-12x+9=0 ?

The solutions to the equation -3x^2-12x+9=0 are x=-2-sqrt(7),x=sqrt(7)-2

Find the zeros of -3x^2-12x+9=0

The zeros of -3x^2-12x+9=0 are x=-2-sqrt(7),x=sqrt(7)-2

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- 3 x^{2} - 12 x + 9 = 0

x = - 2 - 7, x = 7 - 2

Decimal Notation

x = - 4.64575 \dots, x = 0.64575 \dots

Solution steps

- 3 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 3 ) \cdot 9}{2 ( - 3 )}

(- 12)^{2} - 4 (- 3) \cdot 9 = 67

x_{1, 2} = \frac{- ( - 12 ) \pm 6 7}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 7}{2 ( - 3 )}, x_{2} = \frac{- ( - 12 ) - 6 7}{2 ( - 3 )}

x = \frac{- ( - 12 ) + 6 7}{2 ( - 3 )} : - 2 - 7

x = \frac{- ( - 12 ) - 6 7}{2 ( - 3 )} : 7 - 2

The solutions to the quadratic equation are:

x = - 2 - 7, x = 7 - 2

2 x^{2} = 3 - 8 x

4 x^{2} - 13 x = 56

x, x^{2} + k x + x = 8 + k

(x - 5)^{2} - 3 = 0

x^{2} - 4 x + 13 = 0.2 + 3 i

What are the solutions to the equation -3x^2-12x+9=0 ?
The solutions to the equation -3x^2-12x+9=0 are x=-2-sqrt(7),x=sqrt(7)-2
Find the zeros of -3x^2-12x+9=0
The zeros of -3x^2-12x+9=0 are x=-2-sqrt(7),x=sqrt(7)-2