What are the solutions to the equation w(2w-11)-8=0 ?

The solutions to the equation w(2w-11)-8=0 are w=(11+sqrt(185))/4 ,w=(11-sqrt(185))/4

Find the zeros of w(2w-11)-8=0

The zeros of w(2w-11)-8=0 are w=(11+sqrt(185))/4 ,w=(11-sqrt(185))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

w (2 w - 11) - 8 = 0

w = \frac{11 + 185}{4}, w = \frac{11 - 185}{4}

Decimal Notation

w = 6.15036 \dots, w = - 0.65036 \dots

Solution steps

w (2 w - 11) - 8 = 0

Expand

w (2 w - 11) - 8 : 2 w^{2} - 11 w - 8

2 w^{2} - 11 w - 8 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 (- 8) = 185

w_{1, 2} = \frac{- ( - 11 ) \pm 185}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 11 ) + 185}{2 \cdot 2}, w_{2} = \frac{- ( - 11 ) - 185}{2 \cdot 2}

w = \frac{- ( - 11 ) + 185}{2 \cdot 2} : \frac{11 + 185}{4}

w = \frac{- ( - 11 ) - 185}{2 \cdot 2} : \frac{11 - 185}{4}

The solutions to the quadratic equation are:

w = \frac{11 + 185}{4}, w = \frac{11 - 185}{4}

5 r^{2} + 15 r + 7 = 0

20 x^{2} - 20 x = 40

- x^{2} = - 15 - 2 x

9 x^{2} - 225 = 0

(9 x - 14) (8 x + 15) = 7 + 13 x

What are the solutions to the equation w(2w-11)-8=0 ?
The solutions to the equation w(2w-11)-8=0 are w=(11+sqrt(185))/4 ,w=(11-sqrt(185))/4
Find the zeros of w(2w-11)-8=0
The zeros of w(2w-11)-8=0 are w=(11+sqrt(185))/4 ,w=(11-sqrt(185))/4