What are the solutions to the equation (2x+9)^2-25=0 ?

The solutions to the equation (2x+9)^2-25=0 are x=-2,x=-7

Find the zeros of (2x+9)^2-25=0

The zeros of (2x+9)^2-25=0 are x=-2,x=-7

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(2 x + 9)^{2} - 25 = 0

x = - 2, x = - 7

Solution steps

(2 x + 9)^{2} - 25 = 0

Move

25

to the right side

(2 x + 9)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 9 = 25 : x = - 2

Solve

2 x + 9 = - 25 : x = - 7

The solutions to the quadratic equation are:

x = - 2, x = - 7

- 3 t^{2} - t - 10 = - 4 t^{2}

- 4.9 x^{2} - 8 x + 30 = 0

2 x + 3 x^{2} = 0

3 + 2 z = 21 z^{2}

2 x = 14 - 3 x^{2}

What are the solutions to the equation (2x+9)^2-25=0 ?
The solutions to the equation (2x+9)^2-25=0 are x=-2,x=-7
Find the zeros of (2x+9)^2-25=0
The zeros of (2x+9)^2-25=0 are x=-2,x=-7