What are the solutions to the equation (r-1)^2=-5 ?

The solutions to the equation (r-1)^2=-5 are r=sqrt(5)i+1,r=-sqrt(5)i+1

Find the zeros of (r-1)^2=-5

The zeros of (r-1)^2=-5 are r=sqrt(5)i+1,r=-sqrt(5)i+1

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(r - 1)^{2} = - 5

r = 5 i + 1, r = - 5 i + 1

Solution steps

(r - 1)^{2} = - 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

r - 1 = - 5 : r = 5 i + 1

Solve

r - 1 = - - 5 : r = - 5 i + 1

The solutions to the quadratic equation are:

r = 5 i + 1, r = - 5 i + 1

12 x^{2} - 30 x + 18 = 0

2 x^{2} - 4 x + 3 = 0

x^{2} + 8 x = - 7

(6 - r)^{2} + (3 - r)^{2} = r^{2}

3 t^{2} - 10 t - 6 = 2

What are the solutions to the equation (r-1)^2=-5 ?
The solutions to the equation (r-1)^2=-5 are r=sqrt(5)i+1,r=-sqrt(5)i+1
Find the zeros of (r-1)^2=-5
The zeros of (r-1)^2=-5 are r=sqrt(5)i+1,r=-sqrt(5)i+1