What are the solutions to the equation 6x^2-3=8x ?

The solutions to the equation 6x^2-3=8x are x=(4+sqrt(34))/6 ,x=(4-sqrt(34))/6

Find the zeros of 6x^2-3=8x

The zeros of 6x^2-3=8x are x=(4+sqrt(34))/6 ,x=(4-sqrt(34))/6

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6 x^{2} - 3 = 8 x

x = \frac{4 + 34}{6}, x = \frac{4 - 34}{6}

Decimal Notation

x = 1.63849 \dots, x = - 0.30515 \dots

Solution steps

6 x^{2} - 3 = 8 x

Move

8 x

to the left side

6 x^{2} - 3 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

(- 8)^{2} - 4 \cdot 6 (- 3) = 234

x_{1, 2} = \frac{- ( - 8 ) \pm 2 34}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 34}{2 \cdot 6}, x_{2} = \frac{- ( - 8 ) - 2 34}{2 \cdot 6}

x = \frac{- ( - 8 ) + 2 34}{2 \cdot 6} : \frac{4 + 34}{6}

x = \frac{- ( - 8 ) - 2 34}{2 \cdot 6} : \frac{4 - 34}{6}

The solutions to the quadratic equation are:

x = \frac{4 + 34}{6}, x = \frac{4 - 34}{6}

30 x^{2} + 17 x + 2 = 0

15 (p^{2} - 1) = 16 p

2 x^{2} + 5 x + 2 = - 4

x^{2} + 10 = 110

- 7 x^{2} - 8 x + 4 = 0

What are the solutions to the equation 6x^2-3=8x ?
The solutions to the equation 6x^2-3=8x are x=(4+sqrt(34))/6 ,x=(4-sqrt(34))/6
Find the zeros of 6x^2-3=8x
The zeros of 6x^2-3=8x are x=(4+sqrt(34))/6 ,x=(4-sqrt(34))/6