What are the solutions to the equation u^2-7u=-10 ?

The solutions to the equation u^2-7u=-10 are u=5,u=2

Find the zeros of u^2-7u=-10

The zeros of u^2-7u=-10 are u=5,u=2

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u^{2} - 7 u = - 10

u = 5, u = 2

Solution steps

u^{2} - 7 u = - 10

Move

10

to the left side

u^{2} - 7 u + 10 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

u_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, u_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

u = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

u = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

u = 5, u = 2

x^{2} - 22 x = - 120

0.45 x^{2} - 41 x + 1059 = 0

3 x^{2} - 10 = x

4.9 t^{2} - 200 t - 150 = 0

5 x^{2} - 26 x = 24

What are the solutions to the equation u^2-7u=-10 ?
The solutions to the equation u^2-7u=-10 are u=5,u=2
Find the zeros of u^2-7u=-10
The zeros of u^2-7u=-10 are u=5,u=2