What are the solutions to the equation 4x^2+36=0 ?

The solutions to the equation 4x^2+36=0 are x=3i,x=-3i

Find the zeros of 4x^2+36=0

The zeros of 4x^2+36=0 are x=3i,x=-3i

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4 x^{2} + 36 = 0

x = 3 i, x = - 3 i

Solution steps

4 x^{2} + 36 = 0

Move

36

to the right side

4 x^{2} = - 36

Divide both sides by

4

x^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9, x = - - 9

- 9 = 3 i

- - 9 = - 3 i

x = 3 i, x = - 3 i

- 6 x^{2} + 23 x + 4

x^{2} - 1 > x

- x^{3} + 8 x^{2} + 4 x > 32

(7^{2})^{2}

What are the solutions to the equation 4x^2+36=0 ?
The solutions to the equation 4x^2+36=0 are x=3i,x=-3i
Find the zeros of 4x^2+36=0
The zeros of 4x^2+36=0 are x=3i,x=-3i