What are the solutions to the equation x^2+40x+100=0 ?

The solutions to the equation x^2+40x+100=0 are x=10(sqrt(3)-2),x=-10(2+sqrt(3))

Find the zeros of x^2+40x+100=0

The zeros of x^2+40x+100=0 are x=10(sqrt(3)-2),x=-10(2+sqrt(3))

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x^{2} + 40 x + 100 = 0

x = 10 (3 - 2), x = - 10 (2 + 3)

Decimal Notation

x = - 2.67949 \dots, x = - 37.32050 \dots

Solution steps

x^{2} + 40 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot 100}{2 \cdot 1}

4 0^{2} - 4 \cdot 1 \cdot 100 = 203

x_{1, 2} = \frac{- 40 \pm 20 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 40 + 20 3}{2 \cdot 1}, x_{2} = \frac{- 40 - 20 3}{2 \cdot 1}

x = \frac{- 40 + 20 3}{2 \cdot 1} : 10 (3 - 2)

x = \frac{- 40 - 20 3}{2 \cdot 1} : - 10 (2 + 3)

The solutions to the quadratic equation are:

x = 10 (3 - 2), x = - 10 (2 + 3)

3 x^{2} - 6 x - 16 = 0

x - 1 + x (x - 1) = 3 (x - 1)

2 x^{2} - 2 x = 3 x^{2} + 3 x - 50

15 x^{2} - 16 x - 15 = 0

(x + 7) (x - 7) = - 3

What are the solutions to the equation x^2+40x+100=0 ?
The solutions to the equation x^2+40x+100=0 are x=10(sqrt(3)-2),x=-10(2+sqrt(3))
Find the zeros of x^2+40x+100=0
The zeros of x^2+40x+100=0 are x=10(sqrt(3)-2),x=-10(2+sqrt(3))