What are the solutions to the equation 2x^2+36x+34=0 ?

The solutions to the equation 2x^2+36x+34=0 are x=-1,x=-17

Find the zeros of 2x^2+36x+34=0

The zeros of 2x^2+36x+34=0 are x=-1,x=-17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 36 x + 34 = 0

x = - 1, x = - 17

Solution steps

2 x^{2} + 36 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 2 \cdot 34}{2 \cdot 2}

3 6^{2} - 4 \cdot 2 \cdot 34 = 32

x_{1, 2} = \frac{- 36 \pm 32}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 36 + 32}{2 \cdot 2}, x_{2} = \frac{- 36 - 32}{2 \cdot 2}

x = \frac{- 36 + 32}{2 \cdot 2} : - 1

x = \frac{- 36 - 32}{2 \cdot 2} : - 17

The solutions to the quadratic equation are:

x = - 1, x = - 17

3 k^{2} - k - 12 = - 6

x^{2} - 5 x + 3 = 0

(3 k + 4)^{2} + 15 = 0

y^{2} + 8 = 33

4 x^{2} - 5 = x^{2}

What are the solutions to the equation 2x^2+36x+34=0 ?
The solutions to the equation 2x^2+36x+34=0 are x=-1,x=-17
Find the zeros of 2x^2+36x+34=0
The zeros of 2x^2+36x+34=0 are x=-1,x=-17