What are the solutions to the equation -4x-7x^2+15=-5x^2 ?

The solutions to the equation -4x-7x^2+15=-5x^2 are x=-(2+sqrt(34))/2 ,x=(sqrt(34)-2)/2

Find the zeros of -4x-7x^2+15=-5x^2

The zeros of -4x-7x^2+15=-5x^2 are x=-(2+sqrt(34))/2 ,x=(sqrt(34)-2)/2

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- 4 x - 7 x^{2} + 15 = - 5 x^{2}

x = - \frac{2 + 34}{2}, x = \frac{34 - 2}{2}

Decimal Notation

x = - 3.91547 \dots, x = 1.91547 \dots

Solution steps

- 4 x - 7 x^{2} + 15 = - 5 x^{2}

Move

5 x^{2}

to the left side

- 2 x^{2} - 4 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 15}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 15 = 234

x_{1, 2} = \frac{- ( - 4 ) \pm 2 34}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 34}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 2 34}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 2 34}{2 ( - 2 )} : - \frac{2 + 34}{2}

x = \frac{- ( - 4 ) - 2 34}{2 ( - 2 )} : \frac{34 - 2}{2}

The solutions to the quadratic equation are:

x = - \frac{2 + 34}{2}, x = \frac{34 - 2}{2}

2 x^{2} + 6 = 7 x

x^{2} - 25 = 3 x

x^{2} - (2 m - 4) x + 3 - 4 m + m^{2} = 0

x^{2} + 2 x + 1 = 1

- x - 3 = - x^{2} - x + 6

What are the solutions to the equation -4x-7x^2+15=-5x^2 ?
The solutions to the equation -4x-7x^2+15=-5x^2 are x=-(2+sqrt(34))/2 ,x=(sqrt(34)-2)/2
Find the zeros of -4x-7x^2+15=-5x^2
The zeros of -4x-7x^2+15=-5x^2 are x=-(2+sqrt(34))/2 ,x=(sqrt(34)-2)/2