What are the solutions to the equation y(y-13)+6y=18 ?

The solutions to the equation y(y-13)+6y=18 are y=9,y=-2

Find the zeros of y(y-13)+6y=18

The zeros of y(y-13)+6y=18 are y=9,y=-2

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y (y - 13) + 6 y = 18

y = 9, y = - 2

Solution steps

y (y - 13) + 6 y = 18

Expand

y (y - 13) + 6 y : y^{2} - 7 y

y^{2} - 7 y = 18

Move

18

to the left side

y^{2} - 7 y - 18 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

y_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, y_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

y = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

y = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 9, y = - 2

7 (x + 5) (x - 3) - 5 (x + 3) (x - 3) = 0

2 x^{2} + 20 x + 15 = 127

6 x^{2} - 46 x + 312 = 14 x

\frac{n ( n - 3 )}{2} = 2 n

\frac{n ( n - 3 )}{2} = 27

What are the solutions to the equation y(y-13)+6y=18 ?
The solutions to the equation y(y-13)+6y=18 are y=9,y=-2
Find the zeros of y(y-13)+6y=18
The zeros of y(y-13)+6y=18 are y=9,y=-2