What are the solutions to the equation s^2+2s+20=0 ?

The solutions to the equation s^2+2s+20=0 are s=-1+sqrt(19)i,s=-1-sqrt(19)i

Find the zeros of s^2+2s+20=0

The zeros of s^2+2s+20=0 are s=-1+sqrt(19)i,s=-1-sqrt(19)i

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s^{2} + 2 s + 20 = 0

s = - 1 + 19 i, s = - 1 - 19 i

Solution steps

s^{2} + 2 s + 20 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 20 : 219 i

s_{1, 2} = \frac{- 2 \pm 2 19 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 19 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 19 i}{2 \cdot 1}

s = \frac{- 2 + 2 19 i}{2 \cdot 1} : - 1 + 19 i

s = \frac{- 2 - 2 19 i}{2 \cdot 1} : - 1 - 19 i

The solutions to the quadratic equation are:

s = - 1 + 19 i, s = - 1 - 19 i

y^{2} + 2 y + 5 y = 5 y^{2} - 4 y

x, 6 x^{2} - 6 x y + 6 x = 0

4 x^{2} - 36 x + 85 = 0

x^{2} - 7 = 9 x

x^{2} + 6 x - 9 = 6 x

What are the solutions to the equation s^2+2s+20=0 ?
The solutions to the equation s^2+2s+20=0 are s=-1+sqrt(19)i,s=-1-sqrt(19)i
Find the zeros of s^2+2s+20=0
The zeros of s^2+2s+20=0 are s=-1+sqrt(19)i,s=-1-sqrt(19)i