What are the solutions to the equation -4x^2-16x-216=0 ?

The solutions to the equation -4x^2-16x-216=0 are x=-2-5sqrt(2)i,x=-2+5sqrt(2)i

Find the zeros of -4x^2-16x-216=0

The zeros of -4x^2-16x-216=0 are x=-2-5sqrt(2)i,x=-2+5sqrt(2)i

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- 4 x^{2} - 16 x - 216 = 0

x = - 2 - 52 i, x = - 2 + 52 i

Solution steps

- 4 x^{2} - 16 x - 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 4 ) ( - 216 )}{2 ( - 4 )}

Simplify

(- 16)^{2} - 4 (- 4) (- 216) : 402 i

x_{1, 2} = \frac{- ( - 16 ) \pm 40 2 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 40 2 i}{2 ( - 4 )}, x_{2} = \frac{- ( - 16 ) - 40 2 i}{2 ( - 4 )}

x = \frac{- ( - 16 ) + 40 2 i}{2 ( - 4 )} : - 2 - 52 i

x = \frac{- ( - 16 ) - 40 2 i}{2 ( - 4 )} : - 2 + 52 i

The solutions to the quadratic equation are:

x = - 2 - 52 i, x = - 2 + 52 i

- 8 x^{2} - 24 x + 3 = 2

x^{2} - 12 x = 20

x^{2} + x - 6 = x + 3

92 = 20 + 26 t - 2 t^{2}

0 = \frac{- 32 x ^{2}}{13 0 ^{2}} + x

What are the solutions to the equation -4x^2-16x-216=0 ?
The solutions to the equation -4x^2-16x-216=0 are x=-2-5sqrt(2)i,x=-2+5sqrt(2)i
Find the zeros of -4x^2-16x-216=0
The zeros of -4x^2-16x-216=0 are x=-2-5sqrt(2)i,x=-2+5sqrt(2)i