What are the solutions to the equation 3x^2-3=6x-3 ?

The solutions to the equation 3x^2-3=6x-3 are x=2,x=0

Find the zeros of 3x^2-3=6x-3

The zeros of 3x^2-3=6x-3 are x=2,x=0

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3 x^{2} - 3 = 6 x - 3

x = 2, x = 0

Solution steps

3 x^{2} - 3 = 6 x - 3

Move

3

to the left side

3 x^{2} = 6 x

Move

6 x

to the left side

3 x^{2} - 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 0 = 6

x_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6}{2 \cdot 3} : 2

x = \frac{- ( - 6 ) - 6}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

4 + 2 x - x^{2}

3 x^{2} - 2 x = 21

2 r^{2} - r - 11 = - 3

6 x^{2} = - 8 x - 7

(3 x - 3)^{2} - 36 = 0

What are the solutions to the equation 3x^2-3=6x-3 ?
The solutions to the equation 3x^2-3=6x-3 are x=2,x=0
Find the zeros of 3x^2-3=6x-3
The zeros of 3x^2-3=6x-3 are x=2,x=0