What are the solutions to the equation 4t^2-24t=0 ?

The solutions to the equation 4t^2-24t=0 are t=6,t=0

Find the zeros of 4t^2-24t=0

The zeros of 4t^2-24t=0 are t=6,t=0

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4 t^{2} - 24 t = 0

t = 6, t = 0

Solution steps

4 t^{2} - 24 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 24)^{2} - 4 \cdot 4 \cdot 0 = 24

t_{1, 2} = \frac{- ( - 24 ) \pm 24}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- ( - 24 ) + 24}{2 \cdot 4}, t_{2} = \frac{- ( - 24 ) - 24}{2 \cdot 4}

t = \frac{- ( - 24 ) + 24}{2 \cdot 4} : 6

t = \frac{- ( - 24 ) - 24}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

t = 6, t = 0

10 k^{2} = 50

- 2 x^{2} - 42 x = - 10 x + 126

(X + 4)^{2} = 9 (X + 3)

x, 12 x^{2} + 76 x - 115 = 0

2 x^{2} - 8 x - 7

What are the solutions to the equation 4t^2-24t=0 ?
The solutions to the equation 4t^2-24t=0 are t=6,t=0
Find the zeros of 4t^2-24t=0
The zeros of 4t^2-24t=0 are t=6,t=0