What are the solutions to the equation 4x(x-2)+3(x-3)=-3 ?

The solutions to the equation 4x(x-2)+3(x-3)=-3 are x=2,x=-3/4

Find the zeros of 4x(x-2)+3(x-3)=-3

The zeros of 4x(x-2)+3(x-3)=-3 are x=2,x=-3/4

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4 x (x - 2) + 3 (x - 3) = - 3

x = 2, x = - \frac{3}{4}

Decimal Notation

x = 2, x = - 0.75

Solution steps

4 x (x - 2) + 3 (x - 3) = - 3

Expand

4 x (x - 2) + 3 (x - 3) : 4 x^{2} - 5 x - 9

4 x^{2} - 5 x - 9 = - 3

Move

3

to the left side

4 x^{2} - 5 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 6) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 4}

x = \frac{- ( - 5 ) + 11}{2 \cdot 4} : 2

x = \frac{- ( - 5 ) - 11}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{4}

x, y^{4} = (x + 2)^{2}

4 z^{2} - 19 z + 18 = 0

(x - 6) (x - 4) = - 1

20 - t^{2} = 0

x^{2} + x - 12 = 0

What are the solutions to the equation 4x(x-2)+3(x-3)=-3 ?
The solutions to the equation 4x(x-2)+3(x-3)=-3 are x=2,x=-3/4
Find the zeros of 4x(x-2)+3(x-3)=-3
The zeros of 4x(x-2)+3(x-3)=-3 are x=2,x=-3/4