What are the solutions to the equation n^2-6n-7=0 ?

The solutions to the equation n^2-6n-7=0 are n=7,n=-1

Find the zeros of n^2-6n-7=0

The zeros of n^2-6n-7=0 are n=7,n=-1

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n^{2} - 6 n - 7 = 0

n = 7, n = - 1

Solution steps

n^{2} - 6 n - 7 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

n_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, n_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

n = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

n = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

n = 7, n = - 1

x^{2} - 12 x + 64 = 0

b^{2} + 3 b = 0

x^{2} + 6 x - 520 = 0

x^{2} + 6 x + 8 = 3

(y + 3)^{2} = 36

What are the solutions to the equation n^2-6n-7=0 ?
The solutions to the equation n^2-6n-7=0 are n=7,n=-1
Find the zeros of n^2-6n-7=0
The zeros of n^2-6n-7=0 are n=7,n=-1