What are the solutions to the equation (11x-1)^2-4(11x-1)-5=0 ?

The solutions to the equation (11x-1)^2-4(11x-1)-5=0 are x= 6/11 ,x=0

Find the zeros of (11x-1)^2-4(11x-1)-5=0

The zeros of (11x-1)^2-4(11x-1)-5=0 are x= 6/11 ,x=0

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(11 x - 1)^{2} - 4 (11 x - 1) - 5 = 0

x = \frac{6}{11}, x = 0

Decimal Notation

x = 0.54545 \dots, x = 0

Solution steps

(11 x - 1)^{2} - 4 (11 x - 1) - 5 = 0

Expand

(11 x - 1)^{2} - 4 (11 x - 1) - 5 : 121 x^{2} - 66 x

121 x^{2} - 66 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 66 ) \pm ( - 66 ) ^{2} - 4 \cdot 121 \cdot 0}{2 \cdot 121}

(- 66)^{2} - 4 \cdot 121 \cdot 0 = 66

x_{1, 2} = \frac{- ( - 66 ) \pm 66}{2 \cdot 121}

Separate the solutions

x_{1} = \frac{- ( - 66 ) + 66}{2 \cdot 121}, x_{2} = \frac{- ( - 66 ) - 66}{2 \cdot 121}

x = \frac{- ( - 66 ) + 66}{2 \cdot 121} : \frac{6}{11}

x = \frac{- ( - 66 ) - 66}{2 \cdot 121} : 0

The solutions to the quadratic equation are:

x = \frac{6}{11}, x = 0

0 = 2 x^{2} + 4 x - 5

24 = - 0.5 t^{2} + 3.2 t + 22

b^{2} = 34

50 = \frac{3 x ( 20 - x )}{2}

4 x^{2} + 36 x + 31

What are the solutions to the equation (11x-1)^2-4(11x-1)-5=0 ?
The solutions to the equation (11x-1)^2-4(11x-1)-5=0 are x= 6/11 ,x=0
Find the zeros of (11x-1)^2-4(11x-1)-5=0
The zeros of (11x-1)^2-4(11x-1)-5=0 are x= 6/11 ,x=0