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What are the solutions to the equation solvefor x,y^4=x^2+16 ?
The solutions to the equation solvefor x,y^4=x^2+16 are x=sqrt(y^4-16),x=-sqrt(y^4-16)Find the zeros of solvefor x,y^4=x^2+16
The zeros of solvefor x,y^4=x^2+16 are x=sqrt(y^4-16),x=-sqrt(y^4-16)