What are the solutions to the equation solvefor x,y^4=x^2+16 ?

The solutions to the equation solvefor x,y^4=x^2+16 are x=sqrt(y^4-16),x=-sqrt(y^4-16)

Find the zeros of solvefor x,y^4=x^2+16

The zeros of solvefor x,y^4=x^2+16 are x=sqrt(y^4-16),x=-sqrt(y^4-16)

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solve for

x, y^{4} = x^{2} + 16

x = y^{4} - 16, x = - y^{4} - 16

Solution steps

y^{4} = x^{2} + 16

Switch sides

x^{2} + 16 = y^{4}

Move

16

to the right side

x^{2} = y^{4} - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = y^{4} - 16, x = - y^{4} - 16

4 x^{2} - 32 x + 20 = 0

2 x^{2} + 16 x - 11

x^{2} + \frac{1}{4} = 1

2 x^{2} + 6 x + 3

11 m^{2} - 11 m + 3 = 6 m^{2}

What are the solutions to the equation solvefor x,y^4=x^2+16 ?
The solutions to the equation solvefor x,y^4=x^2+16 are x=sqrt(y^4-16),x=-sqrt(y^4-16)
Find the zeros of solvefor x,y^4=x^2+16
The zeros of solvefor x,y^4=x^2+16 are x=sqrt(y^4-16),x=-sqrt(y^4-16)