What are the solutions to the equation 4n^2-7n-85=7 ?

The solutions to the equation 4n^2-7n-85=7 are n= 23/4 ,n=-4

Find the zeros of 4n^2-7n-85=7

The zeros of 4n^2-7n-85=7 are n= 23/4 ,n=-4

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4 n^{2} - 7 n - 85 = 7

n = \frac{23}{4}, n = - 4

Decimal Notation

n = 5.75, n = - 4

Solution steps

4 n^{2} - 7 n - 85 = 7

Move

7

to the left side

4 n^{2} - 7 n - 92 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 ( - 92 )}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 (- 92) = 39

n_{1, 2} = \frac{- ( - 7 ) \pm 39}{2 \cdot 4}

Separate the solutions

n_{1} = \frac{- ( - 7 ) + 39}{2 \cdot 4}, n_{2} = \frac{- ( - 7 ) - 39}{2 \cdot 4}

n = \frac{- ( - 7 ) + 39}{2 \cdot 4} : \frac{23}{4}

n = \frac{- ( - 7 ) - 39}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

n = \frac{23}{4}, n = - 4

2 x^{2} + 2 x - 6 = x^{2}

y, 3 y^{2} - 2 x^{3} = x y

64 - x^{2} = - 17

x (x - 11) + 30 = 0

2 n^{2} - 19 n + 17 = - 3 n^{2}

What are the solutions to the equation 4n^2-7n-85=7 ?
The solutions to the equation 4n^2-7n-85=7 are n= 23/4 ,n=-4
Find the zeros of 4n^2-7n-85=7
The zeros of 4n^2-7n-85=7 are n= 23/4 ,n=-4