What are the solutions to the equation 4x^2-8x=12 ?

The solutions to the equation 4x^2-8x=12 are x=3,x=-1

Find the zeros of 4x^2-8x=12

The zeros of 4x^2-8x=12 are x=3,x=-1

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4 x^{2} - 8 x = 12

x = 3, x = - 1

Solution steps

4 x^{2} - 8 x = 12

Move

12

to the left side

4 x^{2} - 8 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 12) = 16

x_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 16}{2 \cdot 4}

x = \frac{- ( - 8 ) + 16}{2 \cdot 4} : 3

x = \frac{- ( - 8 ) - 16}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

4 w^{2} + 19 w - 5 = 0

x (x - 1) = - 1

4 (t - 1)^{2} - 9 (t - 1) = - 2

x^{2} = - 6 x - 5

a x^{2} - 3 x - 5 = 0

What are the solutions to the equation 4x^2-8x=12 ?
The solutions to the equation 4x^2-8x=12 are x=3,x=-1
Find the zeros of 4x^2-8x=12
The zeros of 4x^2-8x=12 are x=3,x=-1