What are the solutions to the equation 5(x+3)^2=2 ?

The solutions to the equation 5(x+3)^2=2 are x=sqrt(2/5)-3,x=-sqrt(2/5)-3

Find the zeros of 5(x+3)^2=2

The zeros of 5(x+3)^2=2 are x=sqrt(2/5)-3,x=-sqrt(2/5)-3

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5 (x + 3)^{2} = 2

x = \frac{2}{5} - 3, x = - \frac{2}{5} - 3

Solution steps

5 (x + 3)^{2} = 2

Divide both sides by

5

(x + 3)^{2} = \frac{2}{5}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = \frac{2}{5} : x = \frac{2}{5} - 3

Solve

x + 3 = - \frac{2}{5} : x = - \frac{2}{5} - 3

The solutions to the quadratic equation are:

x = \frac{2}{5} - 3, x = - \frac{2}{5} - 3

x, y = 3 - x^{2}

V = π r^{2} h, r

8 x^{2} - 6 x + 3 = 0

2 a^{2} + 3 a - 5 = - 1

x, u = x^{2} - 2

What are the solutions to the equation 5(x+3)^2=2 ?
The solutions to the equation 5(x+3)^2=2 are x=sqrt(2/5)-3,x=-sqrt(2/5)-3
Find the zeros of 5(x+3)^2=2
The zeros of 5(x+3)^2=2 are x=sqrt(2/5)-3,x=-sqrt(2/5)-3