What are the solutions to the equation 15+7k=2k^2 ?

The solutions to the equation 15+7k=2k^2 are k=5,k=-3/2

Find the zeros of 15+7k=2k^2

The zeros of 15+7k=2k^2 are k=5,k=-3/2

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15 + 7 k = 2 k^{2}

k = 5, k = - \frac{3}{2}

Solution steps

15 + 7 k = 2 k^{2}

Switch sides

2 k^{2} = 15 + 7 k

Move

7 k

to the left side

2 k^{2} - 7 k = 15

Move

15

to the left side

2 k^{2} - 7 k - 15 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 15) = 13

k_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 2}, k_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 2}

k = \frac{- ( - 7 ) + 13}{2 \cdot 2} : 5

k = \frac{- ( - 7 ) - 13}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

k = 5, k = - \frac{3}{2}

2 x^{2} + 12 x + 2 = 0

4 p^{2} - 5 p - 6 = - 2

9 x^{2} - 11 = 5

5 x^{2} - 6 = 14

100 = 15 t + \frac{4 t ^{2}}{2}

What are the solutions to the equation 15+7k=2k^2 ?
The solutions to the equation 15+7k=2k^2 are k=5,k=-3/2
Find the zeros of 15+7k=2k^2
The zeros of 15+7k=2k^2 are k=5,k=-3/2