What are the solutions to the equation n(n+6)=520 ?

The solutions to the equation n(n+6)=520 are n=20,n=-26

Find the zeros of n(n+6)=520

The zeros of n(n+6)=520 are n=20,n=-26

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n (n + 6) = 520

n = 20, n = - 26

Solution steps

n (n + 6) = 520

Expand

n (n + 6) : n^{2} + 6 n

n^{2} + 6 n = 520

Move

520

to the left side

n^{2} + 6 n - 520 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 520 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 520) = 46

n_{1, 2} = \frac{- 6 \pm 46}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 6 + 46}{2 \cdot 1}, n_{2} = \frac{- 6 - 46}{2 \cdot 1}

n = \frac{- 6 + 46}{2 \cdot 1} : 20

n = \frac{- 6 - 46}{2 \cdot 1} : - 26

The solutions to the quadratic equation are:

n = 20, n = - 26

x^{2} = 255

(2 x - 1)^{2} + (3 x - 2)^{2} = 5

2 (x - 4)^{2} = 200

4 (x + 1)^{2} = (x - 2)^{2}

2 x^{2} - 4 = 3 x

What are the solutions to the equation n(n+6)=520 ?
The solutions to the equation n(n+6)=520 are n=20,n=-26
Find the zeros of n(n+6)=520
The zeros of n(n+6)=520 are n=20,n=-26