What are the solutions to the equation 3x^2+6x-18=0 ?

The solutions to the equation 3x^2+6x-18=0 are x=-1+sqrt(7),x=-1-sqrt(7)

Find the zeros of 3x^2+6x-18=0

The zeros of 3x^2+6x-18=0 are x=-1+sqrt(7),x=-1-sqrt(7)

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3 x^{2} + 6 x - 18 = 0

x = - 1 + 7, x = - 1 - 7

Decimal Notation

x = 1.64575 \dots, x = - 3.64575 \dots

Solution steps

3 x^{2} + 6 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 18) = 67

x_{1, 2} = \frac{- 6 \pm 6 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6 7}{2 \cdot 3}, x_{2} = \frac{- 6 - 6 7}{2 \cdot 3}

x = \frac{- 6 + 6 7}{2 \cdot 3} : - 1 + 7

x = \frac{- 6 - 6 7}{2 \cdot 3} : - 1 - 7

The solutions to the quadratic equation are:

x = - 1 + 7, x = - 1 - 7

3 x^{2} - 2 = 2 x - 1

(x - 4)^{2} = (3 - x) (1 + 2 x)

t, e = \frac{1}{2} a t^{2}

9 x^{2} - 73 x + 73 = 0

(x - 3) (1 - x) = - 3

What are the solutions to the equation 3x^2+6x-18=0 ?
The solutions to the equation 3x^2+6x-18=0 are x=-1+sqrt(7),x=-1-sqrt(7)
Find the zeros of 3x^2+6x-18=0
The zeros of 3x^2+6x-18=0 are x=-1+sqrt(7),x=-1-sqrt(7)