What are the solutions to the equation x^2-120x+3600=0 ?

The solutions to the equation x^2-120x+3600=0 are x=60

Find the zeros of x^2-120x+3600=0

The zeros of x^2-120x+3600=0 are x=60

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 120 x + 3600 = 0

x = 60

Solution steps

x^{2} - 120 x + 3600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 1 \cdot 3600}{2 \cdot 1}

(- 120)^{2} - 4 \cdot 1 \cdot 3600 = 0

x_{1, 2} = \frac{- ( - 120 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 120 )}{2 \cdot 1}

\frac{- ( - 120 )}{2 \cdot 1} = 60

x = 60

The solution to the quadratic equation is:

x = 60

x^{2} - 3 x = 2 x + 14

23 = x^{2} + 7

x, 432 = 3 x^{2}

X^{2} + 3 X + 2 = 0

12 x^{2} + 25 x = 7

What are the solutions to the equation x^2-120x+3600=0 ?
The solutions to the equation x^2-120x+3600=0 are x=60
Find the zeros of x^2-120x+3600=0
The zeros of x^2-120x+3600=0 are x=60