What are the solutions to the equation 4x^2+1=9 ?

The solutions to the equation 4x^2+1=9 are x=sqrt(2),x=-sqrt(2)

Find the zeros of 4x^2+1=9

The zeros of 4x^2+1=9 are x=sqrt(2),x=-sqrt(2)

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4 x^{2} + 1 = 9

x = 2, x = - 2

Solution steps

4 x^{2} + 1 = 9

Move

1

to the right side

4 x^{2} = 8

Divide both sides by

4

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

3 x (2 x - 5) = 3

2 s^{2} - 98 = 0

6 x^{2} + 23 x - 4 = 0

67 = \frac{v ^{2}}{5.7}

(2 x + 1) (x - 1) = (3 x - 1) (x + 1)

What are the solutions to the equation 4x^2+1=9 ?
The solutions to the equation 4x^2+1=9 are x=sqrt(2),x=-sqrt(2)
Find the zeros of 4x^2+1=9
The zeros of 4x^2+1=9 are x=sqrt(2),x=-sqrt(2)