What are the solutions to the equation solvefor x,x^2+y^2-10x+9=0 ?

The solutions to the equation solvefor x,x^2+y^2-10x+9=0 are x=5+sqrt(-y^2+16),x=5-sqrt(-y^2+16)

Find the zeros of solvefor x,x^2+y^2-10x+9=0

The zeros of solvefor x,x^2+y^2-10x+9=0 are x=5+sqrt(-y^2+16),x=5-sqrt(-y^2+16)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} + y^{2} - 10 x + 9 = 0

x = 5 + - y^{2} + 16, x = 5 - - y^{2} + 16

Solution steps

x^{2} + y^{2} - 10 x + 9 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 10 x + y^{2} + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( y ^{2} + 9 )}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot (y^{2} + 9) : 2 - y^{2} + 16

x_{1, 2} = \frac{- ( - 10 ) \pm 2 - y ^{2} + 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 - y ^{2} + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 - y ^{2} + 16}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 - y ^{2} + 16}{2 \cdot 1} : 5 + - y^{2} + 16

x = \frac{- ( - 10 ) - 2 - y ^{2} + 16}{2 \cdot 1} : 5 - - y^{2} + 16

The solutions to the quadratic equation are:

x = 5 + - y^{2} + 16, x = 5 - - y^{2} + 16

25 x^{2} - 10 x = 0

x (2 x - 7) = 4 (x - 3)

x^{2} - 2 x - 240 = 0

x^{2} - 2 (k - 3) x + 4 k = 0

68.2 = 39.2 t - 4.9 t^{2}

What are the solutions to the equation solvefor x,x^2+y^2-10x+9=0 ?
The solutions to the equation solvefor x,x^2+y^2-10x+9=0 are x=5+sqrt(-y^2+16),x=5-sqrt(-y^2+16)
Find the zeros of solvefor x,x^2+y^2-10x+9=0
The zeros of solvefor x,x^2+y^2-10x+9=0 are x=5+sqrt(-y^2+16),x=5-sqrt(-y^2+16)