What are the solutions to the equation x^2-3x=7x^2+5x ?

The solutions to the equation x^2-3x=7x^2+5x are x=-4/3 ,x=0

Find the zeros of x^2-3x=7x^2+5x

The zeros of x^2-3x=7x^2+5x are x=-4/3 ,x=0

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x^{2} - 3 x = 7 x^{2} + 5 x

x = - \frac{4}{3}, x = 0

Decimal Notation

x = - 1.33333 \dots, x = 0

Solution steps

x^{2} - 3 x = 7 x^{2} + 5 x

Move

5 x

to the left side

x^{2} - 8 x = 7 x^{2}

Move

7 x^{2}

to the left side

- 6 x^{2} - 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

(- 8)^{2} - 4 (- 6) \cdot 0 = 8

x_{1, 2} = \frac{- ( - 8 ) \pm 8}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8}{2 ( - 6 )}, x_{2} = \frac{- ( - 8 ) - 8}{2 ( - 6 )}

x = \frac{- ( - 8 ) + 8}{2 ( - 6 )} : - \frac{4}{3}

x = \frac{- ( - 8 ) - 8}{2 ( - 6 )} : 0

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = 0

2 x (x - 5) = - 3 x - 3

(x - 6) (x + 2) + x^{2} + 4 = (x - 4) (x - 1)

x^{2} - 8 x + 12 = 0

x^{2} - 13 x = 30

x^{2} - 6 (x - 1) = 7 (1 - x)

What are the solutions to the equation x^2-3x=7x^2+5x ?
The solutions to the equation x^2-3x=7x^2+5x are x=-4/3 ,x=0
Find the zeros of x^2-3x=7x^2+5x
The zeros of x^2-3x=7x^2+5x are x=-4/3 ,x=0