What are the solutions to the equation 2(x+3)^2+4=0 ?

The solutions to the equation 2(x+3)^2+4=0 are x=sqrt(2)i-3,x=-sqrt(2)i-3

Find the zeros of 2(x+3)^2+4=0

The zeros of 2(x+3)^2+4=0 are x=sqrt(2)i-3,x=-sqrt(2)i-3

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2 (x + 3)^{2} + 4 = 0

x = 2 i - 3, x = - 2 i - 3

Solution steps

2 (x + 3)^{2} + 4 = 0

Move

4

to the right side

2 (x + 3)^{2} = - 4

Divide both sides by

2

(x + 3)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 2 : x = 2 i - 3

Solve

x + 3 = - - 2 : x = - 2 i - 3

The solutions to the quadratic equation are:

x = 2 i - 3, x = - 2 i - 3

(x - 11)^{2} = 0

x^{2} - 25 = 25

x^{2} + 4 x + 4 = x - 8

y, s (y) = 7 yy + 9

t (t - 4) = 0

What are the solutions to the equation 2(x+3)^2+4=0 ?
The solutions to the equation 2(x+3)^2+4=0 are x=sqrt(2)i-3,x=-sqrt(2)i-3
Find the zeros of 2(x+3)^2+4=0
The zeros of 2(x+3)^2+4=0 are x=sqrt(2)i-3,x=-sqrt(2)i-3