What are the solutions to the equation t^2=4 ?

The solutions to the equation t^2=4 are t=2,t=-2

Find the zeros of t^2=4

The zeros of t^2=4 are t=2,t=-2

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t^{2} = 4

t = 2, t = - 2

Solution steps

t^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 4, t = - 4

4 = 2

- 4 = - 2

t = 2, t = - 2

\frac{2}{5} x - x + \frac{5}{10} = 3 x - \frac{25}{2}

0^{2} - 3

\frac{p}{7 a - 14} + \frac{1}{2 - a}

6 x + 9

\frac{9}{7} + \frac{3}{4}

What are the solutions to the equation t^2=4 ?
The solutions to the equation t^2=4 are t=2,t=-2
Find the zeros of t^2=4
The zeros of t^2=4 are t=2,t=-2