What are the solutions to the equation x^2-18x+81=12 ?

The solutions to the equation x^2-18x+81=12 are x=9+2sqrt(3),x=9-2sqrt(3)

Find the zeros of x^2-18x+81=12

The zeros of x^2-18x+81=12 are x=9+2sqrt(3),x=9-2sqrt(3)

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x^{2} - 18 x + 81 = 12

x = 9 + 23, x = 9 - 23

Solution steps

x^{2} - 18 x + 81 = 12

Move

12

to the left side

x^{2} - 18 x + 69 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 69}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 69 = 43

x_{1, 2} = \frac{- ( - 18 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 18 ) + 4 3}{2 \cdot 1} : 9 + 23

x = \frac{- ( - 18 ) - 4 3}{2 \cdot 1} : 9 - 23

The solutions to the quadratic equation are:

x = 9 + 23, x = 9 - 23

- x^{2} - 3 x + 9 = - 9 + 6 x - 2 x^{2}

x^{2} - (k - 3) x - 6 = 0

x, y^{2} = 4 x^{2} + 9 z^{2}

- 100 = - 4.9 t^{2}

x^{2} - 13 = 60

What are the solutions to the equation x^2-18x+81=12 ?
The solutions to the equation x^2-18x+81=12 are x=9+2sqrt(3),x=9-2sqrt(3)
Find the zeros of x^2-18x+81=12
The zeros of x^2-18x+81=12 are x=9+2sqrt(3),x=9-2sqrt(3)