What are the solutions to the equation 4x^2-3(5x-1)=0 ?

The solutions to the equation 4x^2-3(5x-1)=0 are x=(15+sqrt(177))/8 ,x=(15-sqrt(177))/8

Find the zeros of 4x^2-3(5x-1)=0

The zeros of 4x^2-3(5x-1)=0 are x=(15+sqrt(177))/8 ,x=(15-sqrt(177))/8

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4 x^{2} - 3 (5 x - 1) = 0

x = \frac{15 + 177}{8}, x = \frac{15 - 177}{8}

Solution steps

4 x^{2} - 3 (5 x - 1) = 0

Expand

4 x^{2} - 3 (5 x - 1) : 4 x^{2} - 15 x + 3

4 x^{2} - 15 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(- 15)^{2} - 4 \cdot 4 \cdot 3 = 177

x_{1, 2} = \frac{- ( - 15 ) \pm 177}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 177}{2 \cdot 4}, x_{2} = \frac{- ( - 15 ) - 177}{2 \cdot 4}

x = \frac{- ( - 15 ) + 177}{2 \cdot 4} : \frac{15 + 177}{8}

x = \frac{- ( - 15 ) - 177}{2 \cdot 4} : \frac{15 - 177}{8}

The solutions to the quadratic equation are:

x = \frac{15 + 177}{8}, x = \frac{15 - 177}{8}

- 0.1 x^{2} + 14 x + 3 = 1000

x (x - 5) = 4 x

16 x^{2} + 22 = 0

x^{2} + a x - b x = ab

3 x^{2} - 60 x + 741 = 0

What are the solutions to the equation 4x^2-3(5x-1)=0 ?
The solutions to the equation 4x^2-3(5x-1)=0 are x=(15+sqrt(177))/8 ,x=(15-sqrt(177))/8
Find the zeros of 4x^2-3(5x-1)=0
The zeros of 4x^2-3(5x-1)=0 are x=(15+sqrt(177))/8 ,x=(15-sqrt(177))/8