What are the solutions to the equation 6n^2+4n-1=0 ?

The solutions to the equation 6n^2+4n-1=0 are n=(-2+sqrt(10))/6 ,n=-(2+sqrt(10))/6

Find the zeros of 6n^2+4n-1=0

The zeros of 6n^2+4n-1=0 are n=(-2+sqrt(10))/6 ,n=-(2+sqrt(10))/6

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6 n^{2} + 4 n - 1 = 0

n = \frac{- 2 + 10}{6}, n = - \frac{2 + 10}{6}

Solution steps

6 n^{2} + 4 n - 1 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

4^{2} - 4 \cdot 6 (- 1) = 210

n_{1, 2} = \frac{- 4 \pm 2 10}{2 \cdot 6}

Separate the solutions

n_{1} = \frac{- 4 + 2 10}{2 \cdot 6}, n_{2} = \frac{- 4 - 2 10}{2 \cdot 6}

n = \frac{- 4 + 2 10}{2 \cdot 6} : \frac{- 2 + 10}{6}

n = \frac{- 4 - 2 10}{2 \cdot 6} : - \frac{2 + 10}{6}

The solutions to the quadratic equation are:

n = \frac{- 2 + 10}{6}, n = - \frac{2 + 10}{6}

k^{2} - 2 k - 3 = 0

6 x^{2} - 12 x + 1476 = 0

x, x + 2 x^{2} - 4 = - 7 x + 6

3 x + 2 x^{2} = 7

x^{2} - 2.454 x + 1.5 = 0

What are the solutions to the equation 6n^2+4n-1=0 ?
The solutions to the equation 6n^2+4n-1=0 are n=(-2+sqrt(10))/6 ,n=-(2+sqrt(10))/6
Find the zeros of 6n^2+4n-1=0
The zeros of 6n^2+4n-1=0 are n=(-2+sqrt(10))/6 ,n=-(2+sqrt(10))/6