What are the solutions to the equation 3c^2+c-11=-4 ?

The solutions to the equation 3c^2+c-11=-4 are c=(-1+sqrt(85))/6 ,c=(-1-sqrt(85))/6

Find the zeros of 3c^2+c-11=-4

The zeros of 3c^2+c-11=-4 are c=(-1+sqrt(85))/6 ,c=(-1-sqrt(85))/6

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3 c^{2} + c - 11 = - 4

c = \frac{- 1 + 85}{6}, c = \frac{- 1 - 85}{6}

Solution steps

3 c^{2} + c - 11 = - 4

Move

4

to the left side

3 c^{2} + c - 7 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 7) = 85

c_{1, 2} = \frac{- 1 \pm 85}{2 \cdot 3}

Separate the solutions

c_{1} = \frac{- 1 + 85}{2 \cdot 3}, c_{2} = \frac{- 1 - 85}{2 \cdot 3}

c = \frac{- 1 + 85}{2 \cdot 3} : \frac{- 1 + 85}{6}

c = \frac{- 1 - 85}{2 \cdot 3} : \frac{- 1 - 85}{6}

The solutions to the quadratic equation are:

c = \frac{- 1 + 85}{6}, c = \frac{- 1 - 85}{6}

x (5 x + 1.5) - 2.6 = 1.6 x (2.5 x + 0.5)

- 5 x^{2} - 10 x = - 315

\frac{z ( z + 1 )}{2} = 21

a^{2} + 7 a + 6 = 0

7 x^{2} = 12 x

What are the solutions to the equation 3c^2+c-11=-4 ?
The solutions to the equation 3c^2+c-11=-4 are c=(-1+sqrt(85))/6 ,c=(-1-sqrt(85))/6
Find the zeros of 3c^2+c-11=-4
The zeros of 3c^2+c-11=-4 are c=(-1+sqrt(85))/6 ,c=(-1-sqrt(85))/6