What are the solutions to the equation z^2+z-3=0 ?

The solutions to the equation z^2+z-3=0 are z=(-1+sqrt(13))/2 ,z=(-1-sqrt(13))/2

Find the zeros of z^2+z-3=0

The zeros of z^2+z-3=0 are z=(-1+sqrt(13))/2 ,z=(-1-sqrt(13))/2

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z^{2} + z - 3 = 0

z = \frac{- 1 + 13}{2}, z = \frac{- 1 - 13}{2}

Decimal Notation

z = 1.30277 \dots, z = - 2.30277 \dots

Solution steps

z^{2} + z - 3 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 3) = 13

z_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 1 + 13}{2 \cdot 1}, z_{2} = \frac{- 1 - 13}{2 \cdot 1}

z = \frac{- 1 + 13}{2 \cdot 1} : \frac{- 1 + 13}{2}

z = \frac{- 1 - 13}{2 \cdot 1} : \frac{- 1 - 13}{2}

The solutions to the quadratic equation are:

z = \frac{- 1 + 13}{2}, z = \frac{- 1 - 13}{2}

2 (y^{2} + 3) = 11 - 13 y

6 (1 - x) + 2 = 3 x^{2} - 17

d^{2} - 18 = 0

x^{2} + 4 x - 48 = 0

9 a^{2} - 40 = 0

What are the solutions to the equation z^2+z-3=0 ?
The solutions to the equation z^2+z-3=0 are z=(-1+sqrt(13))/2 ,z=(-1-sqrt(13))/2
Find the zeros of z^2+z-3=0
The zeros of z^2+z-3=0 are z=(-1+sqrt(13))/2 ,z=(-1-sqrt(13))/2