What are the solutions to the equation 8x^2-16x-4=0 ?

The solutions to the equation 8x^2-16x-4=0 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2

Find the zeros of 8x^2-16x-4=0

The zeros of 8x^2-16x-4=0 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2

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8 x^{2} - 16 x - 4 = 0

x = \frac{2 + 6}{2}, x = \frac{2 - 6}{2}

Decimal Notation

x = 2.22474 \dots, x = - 0.22474 \dots

Solution steps

8 x^{2} - 16 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 8 ( - 4 )}{2 \cdot 8}

(- 16)^{2} - 4 \cdot 8 (- 4) = 86

x_{1, 2} = \frac{- ( - 16 ) \pm 8 6}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8 6}{2 \cdot 8}, x_{2} = \frac{- ( - 16 ) - 8 6}{2 \cdot 8}

x = \frac{- ( - 16 ) + 8 6}{2 \cdot 8} : \frac{2 + 6}{2}

x = \frac{- ( - 16 ) - 8 6}{2 \cdot 8} : \frac{2 - 6}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 6}{2}, x = \frac{2 - 6}{2}

(2 x - 6)^{2} - 64 = 0

y, 2 x - y^{2} = 7

5 x^{2} - 18 x + 12 = 0

2 (x + 6)^{2} = 24

(2 - x) (2 + x) = 1

What are the solutions to the equation 8x^2-16x-4=0 ?
The solutions to the equation 8x^2-16x-4=0 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2
Find the zeros of 8x^2-16x-4=0
The zeros of 8x^2-16x-4=0 are x=(2+sqrt(6))/2 ,x=(2-sqrt(6))/2