What are the solutions to the equation 4x-12x^2=0 ?

The solutions to the equation 4x-12x^2=0 are x=0,x= 1/3

Find the zeros of 4x-12x^2=0

The zeros of 4x-12x^2=0 are x=0,x= 1/3

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4 x - 12 x^{2} = 0

x = 0, x = \frac{1}{3}

Solution steps

4 x - 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 12 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

4^{2} - 4 (- 12) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 12 )}, x_{2} = \frac{- 4 - 4}{2 ( - 12 )}

x = \frac{- 4 + 4}{2 ( - 12 )} : 0

x = \frac{- 4 - 4}{2 ( - 12 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{3}

x^{3} + 18 x^{2} + 81 x

8 x + \frac{3}{4} < 2

10 y^{4} + 9 y x

9 - 2 x - 9 - 16 x = - 14 x - 7 - 4 x - 11

8 v - 21 = 2 v - 9

What are the solutions to the equation 4x-12x^2=0 ?
The solutions to the equation 4x-12x^2=0 are x=0,x= 1/3
Find the zeros of 4x-12x^2=0
The zeros of 4x-12x^2=0 are x=0,x= 1/3