What are the solutions to the equation x^2+16x=-59 ?

The solutions to the equation x^2+16x=-59 are x=-8+sqrt(5),x=-8-sqrt(5)

Find the zeros of x^2+16x=-59

The zeros of x^2+16x=-59 are x=-8+sqrt(5),x=-8-sqrt(5)

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x^{2} + 16 x = - 59

x = - 8 + 5, x = - 8 - 5

Solution steps

x^{2} + 16 x = - 59

Move

59

to the left side

x^{2} + 16 x + 59 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 59}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 59 = 25

x_{1, 2} = \frac{- 16 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 5}{2 \cdot 1}

x = \frac{- 16 + 2 5}{2 \cdot 1} : - 8 + 5

x = \frac{- 16 - 2 5}{2 \cdot 1} : - 8 - 5

The solutions to the quadratic equation are:

x = - 8 + 5, x = - 8 - 5

3 (4 b^{2} - 7) = - 2 b - 8

4 x^{2} + 20 x

x - 7 = (x - 1)^{2}

x, 25 x^{2} + k x + 4 = 0

4 x^{2} + 20 = 10 x + 3 x^{2} - 4

What are the solutions to the equation x^2+16x=-59 ?
The solutions to the equation x^2+16x=-59 are x=-8+sqrt(5),x=-8-sqrt(5)
Find the zeros of x^2+16x=-59
The zeros of x^2+16x=-59 are x=-8+sqrt(5),x=-8-sqrt(5)