What are the solutions to the equation (x+3)^2-169=0 ?

The solutions to the equation (x+3)^2-169=0 are x=10,x=-16

Find the zeros of (x+3)^2-169=0

The zeros of (x+3)^2-169=0 are x=10,x=-16

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(x + 3)^{2} - 169 = 0

x = 10, x = - 16

Solution steps

(x + 3)^{2} - 169 = 0

Move

169

to the right side

(x + 3)^{2} = 169

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 169 : x = 10

Solve

x + 3 = - 169 : x = - 16

The solutions to the quadratic equation are:

x = 10, x = - 16

- 3 x^{2} - 2 x - 1 = 0

x^{2} + a^{2} - b x + ab = 0

3 + 5 d = 4 d^{2}

(2 r - 5)^{2} = 0

21 k^{2} + 4 k = - 3 + 6 k + 9 k^{2}

What are the solutions to the equation (x+3)^2-169=0 ?
The solutions to the equation (x+3)^2-169=0 are x=10,x=-16
Find the zeros of (x+3)^2-169=0
The zeros of (x+3)^2-169=0 are x=10,x=-16