What are the solutions to the equation solvefor x,y=(x^2)/4 ?

The solutions to the equation solvefor x,y=(x^2)/4 are x=2sqrt(y),x=-2sqrt(y)

Find the zeros of solvefor x,y=(x^2)/4

The zeros of solvefor x,y=(x^2)/4 are x=2sqrt(y),x=-2sqrt(y)

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solve for

x, y = \frac{x ^{2}}{4}

x = 2 y, x = - 2 y

Solution steps

y = \frac{x ^{2}}{4}

Switch sides

\frac{x ^{2}}{4} = y

Multiply both sides by

4

x^{2} = 4 y

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 4 y, x = - 4 y

Simplify

4 y : 2 y

Simplify

- 4 y : - 2 y

x = 2 y, x = - 2 y

(x - 4)^{2} + 3 (x + 1) (x - 2) = 8

x, f (x + 2) = x^{2} - x

r^{2} - 144 = 0

4 x^{2} + 26 x + 30 = 0

- 5 x^{2} + 10 = 0

What are the solutions to the equation solvefor x,y=(x^2)/4 ?
The solutions to the equation solvefor x,y=(x^2)/4 are x=2sqrt(y),x=-2sqrt(y)
Find the zeros of solvefor x,y=(x^2)/4
The zeros of solvefor x,y=(x^2)/4 are x=2sqrt(y),x=-2sqrt(y)