What are the solutions to the equation c^2+c=2 ?

The solutions to the equation c^2+c=2 are c=1,c=-2

Find the zeros of c^2+c=2

The zeros of c^2+c=2 are c=1,c=-2

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c^{2} + c = 2

c = 1, c = - 2

Solution steps

c^{2} + c = 2

Move

2

to the left side

c^{2} + c - 2 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

c_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 1 + 3}{2 \cdot 1}, c_{2} = \frac{- 1 - 3}{2 \cdot 1}

c = \frac{- 1 + 3}{2 \cdot 1} : 1

c = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

c = 1, c = - 2

(3 - X)^{2} + X^{2} = 2 (5 - X)

8 x^{2} - 20 = 0

\frac{x ^{2}}{2} = x

- 2 x^{2} = - 72

x^{2} - 4 x - 7

What are the solutions to the equation c^2+c=2 ?
The solutions to the equation c^2+c=2 are c=1,c=-2
Find the zeros of c^2+c=2
The zeros of c^2+c=2 are c=1,c=-2