What are the solutions to the equation -4x^2-2x+9=0 ?

The solutions to the equation -4x^2-2x+9=0 are x=-(1+sqrt(37))/4 ,x=(sqrt(37)-1)/4

Find the zeros of -4x^2-2x+9=0

The zeros of -4x^2-2x+9=0 are x=-(1+sqrt(37))/4 ,x=(sqrt(37)-1)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 x^{2} - 2 x + 9 = 0

x = - \frac{1 + 37}{4}, x = \frac{37 - 1}{4}

Decimal Notation

x = - 1.77069 \dots, x = 1.27069 \dots

Solution steps

- 4 x^{2} - 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 4 ) \cdot 9}{2 ( - 4 )}

(- 2)^{2} - 4 (- 4) \cdot 9 = 237

x_{1, 2} = \frac{- ( - 2 ) \pm 2 37}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 37}{2 ( - 4 )}, x_{2} = \frac{- ( - 2 ) - 2 37}{2 ( - 4 )}

x = \frac{- ( - 2 ) + 2 37}{2 ( - 4 )} : - \frac{1 + 37}{4}

x = \frac{- ( - 2 ) - 2 37}{2 ( - 4 )} : \frac{37 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 37}{4}, x = \frac{37 - 1}{4}

3 (2 x + 1)^{2} + 2 = 7

w^{2} + 50 = - 15 w

4 x^{2} + 7 x - 7 = 0

3 x^{2} - 5 x + 1

(6 x - 3) (2 x + 4) = 3

What are the solutions to the equation -4x^2-2x+9=0 ?
The solutions to the equation -4x^2-2x+9=0 are x=-(1+sqrt(37))/4 ,x=(sqrt(37)-1)/4
Find the zeros of -4x^2-2x+9=0
The zeros of -4x^2-2x+9=0 are x=-(1+sqrt(37))/4 ,x=(sqrt(37)-1)/4