What are the solutions to the equation 3x+2x^2=5x^2-6 ?

The solutions to the equation 3x+2x^2=5x^2-6 are x=-1,x=2

Find the zeros of 3x+2x^2=5x^2-6

The zeros of 3x+2x^2=5x^2-6 are x=-1,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x + 2 x^{2} = 5 x^{2} - 6

x = - 1, x = 2

Solution steps

3 x + 2 x^{2} = 5 x^{2} - 6

Move

6

to the left side

3 x + 2 x^{2} + 6 = 5 x^{2}

Move

5 x^{2}

to the left side

- 3 x^{2} + 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 3 ) \cdot 6}{2 ( - 3 )}

3^{2} - 4 (- 3) \cdot 6 = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 ( - 3 )}, x_{2} = \frac{- 3 - 9}{2 ( - 3 )}

x = \frac{- 3 + 9}{2 ( - 3 )} : - 1

x = \frac{- 3 - 9}{2 ( - 3 )} : 2

The solutions to the quadratic equation are:

x = - 1, x = 2

x^{2} - 3 a x + a^{2} = 0

15 + (x - 4)^{2} = 7

3 (x^{2} - 3) = 35 x + 19

6 v^{2} + 3 = - 2 v

20 x^{2} + 6 x - 8 = 0

What are the solutions to the equation 3x+2x^2=5x^2-6 ?
The solutions to the equation 3x+2x^2=5x^2-6 are x=-1,x=2
Find the zeros of 3x+2x^2=5x^2-6
The zeros of 3x+2x^2=5x^2-6 are x=-1,x=2