What are the solutions to the equation (m+8)(m-9)=-16 ?

The solutions to the equation (m+8)(m-9)=-16 are m=8,m=-7

Find the zeros of (m+8)(m-9)=-16

The zeros of (m+8)(m-9)=-16 are m=8,m=-7

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(m + 8) (m - 9) = - 16

m = 8, m = - 7

Solution steps

(m + 8) (m - 9) = - 16

Expand

(m + 8) (m - 9) : m^{2} - m - 72

m^{2} - m - 72 = - 16

Move

16

to the left side

m^{2} - m - 56 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 56) = 15

m_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 15}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 15}{2 \cdot 1}

m = \frac{- ( - 1 ) + 15}{2 \cdot 1} : 8

m = \frac{- ( - 1 ) - 15}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

m = 8, m = - 7

8 x^{2} - 16 x + 3

y^{2} - 8 y + 22 = 0

(x + 3) (x - 2) = 1

x^{2} + 10 x = 3

4 x^{2} + 5 = 54

What are the solutions to the equation (m+8)(m-9)=-16 ?
The solutions to the equation (m+8)(m-9)=-16 are m=8,m=-7
Find the zeros of (m+8)(m-9)=-16
The zeros of (m+8)(m-9)=-16 are m=8,m=-7