What are the solutions to the equation x^2+15x=x+98 ?

The solutions to the equation x^2+15x=x+98 are x=7(sqrt(3)-1),x=-7(1+sqrt(3))

Find the zeros of x^2+15x=x+98

The zeros of x^2+15x=x+98 are x=7(sqrt(3)-1),x=-7(1+sqrt(3))

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x^{2} + 15 x = x + 98

x = 7 (3 - 1), x = - 7 (1 + 3)

Decimal Notation

x = 5.12435 \dots, x = - 19.12435 \dots

Solution steps

x^{2} + 15 x = x + 98

Move

98

to the left side

x^{2} + 15 x - 98 = x

Move

x

to the left side

x^{2} + 14 x - 98 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 98 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 98) = 143

x_{1, 2} = \frac{- 14 \pm 14 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 14 3}{2 \cdot 1}, x_{2} = \frac{- 14 - 14 3}{2 \cdot 1}

x = \frac{- 14 + 14 3}{2 \cdot 1} : 7 (3 - 1)

x = \frac{- 14 - 14 3}{2 \cdot 1} : - 7 (1 + 3)

The solutions to the quadratic equation are:

x = 7 (3 - 1), x = - 7 (1 + 3)

x^{2} + 3 x + 5 = 0

x^{2} - 11 x - 42 = 0

- x^{2} = x^{2} - 8

x, e^{t} = x^{2}

- 3 (4 x - 12) (20 + 5 x) = 0

What are the solutions to the equation x^2+15x=x+98 ?
The solutions to the equation x^2+15x=x+98 are x=7(sqrt(3)-1),x=-7(1+sqrt(3))
Find the zeros of x^2+15x=x+98
The zeros of x^2+15x=x+98 are x=7(sqrt(3)-1),x=-7(1+sqrt(3))