What are the solutions to the equation -2(x-2)(7x-2)=0 ?

The solutions to the equation -2(x-2)(7x-2)=0 are x=2,x= 2/7

Find the zeros of -2(x-2)(7x-2)=0

The zeros of -2(x-2)(7x-2)=0 are x=2,x= 2/7

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- 2 (x - 2) (7 x - 2) = 0

x = 2, x = \frac{2}{7}

Decimal Notation

x = 2, x = 0.28571 \dots

Solution steps

- 2 (x - 2) (7 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 7 x - 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

7 x - 2 = 0 : x = \frac{2}{7}

The solutions to the quadratic equation are:

x = 2, x = \frac{2}{7}

x^{2} + 8 x = - 5

x, C y^{2} = x^{2} + y

u^{2} - 9 = (\frac{24}{25}) u^{2}

3 k^{2} - 19 = 15 k - 1

(2 x + 3)^{2} = - 4

What are the solutions to the equation -2(x-2)(7x-2)=0 ?
The solutions to the equation -2(x-2)(7x-2)=0 are x=2,x= 2/7
Find the zeros of -2(x-2)(7x-2)=0
The zeros of -2(x-2)(7x-2)=0 are x=2,x= 2/7