What is the answer to |(x+3)/4-1/2 |=3 ?

The answer to |(x+3)/4-1/2 |=3 is x=-13\lor x=11

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|(x+3)/4-1/2 |=3

\frac{x + 3}{4} - \frac{1}{2} = 3

x = - 13 or x = 11

Solution steps

\frac{x + 3}{4} - \frac{1}{2} = 3

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

\frac{x + 3}{4} - \frac{1}{2} = - 3 or \frac{x + 3}{4} - \frac{1}{2} = 3

\frac{x + 3}{4} - \frac{1}{2} = - 3 or \frac{x + 3}{4} - \frac{1}{2} = 3

x = - 13 or x = 11

- 6 + \frac{3}{2}

1 - 4 (a + 1) = 7 + a

15 \cdot 5

\frac{x}{2} \geq 1 - \frac{x}{4}

10000 \cdot \frac{( 1 - \frac{( 1 )}{( 1.1 ) ^{10}} )}{0.1}

What is the answer to |(x+3)/4-1/2 |=3 ?
The answer to |(x+3)/4-1/2 |=3 is x=-13\lor x=11
Solve for x: |(x+3)/4-1/2 |=3
The solution is x=-13\lor x=11