What are the solutions to the equation (-5)^2+(2)^2=D^2 ?

The solutions to the equation (-5)^2+(2)^2=D^2 are D=sqrt(29),D=-sqrt(29)

Find the zeros of (-5)^2+(2)^2=D^2

The zeros of (-5)^2+(2)^2=D^2 are D=sqrt(29),D=-sqrt(29)

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(- 5)^{2} + (2)^{2} = D^{2}

D = 29, D = - 29

Solution steps

(- 5)^{2} + (2)^{2} = D^{2}

Switch sides

D^{2} = (- 5)^{2} + (2)^{2}

Simplify

(- 5)^{2} + 2^{2} : 29

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

D = 29, D = - 29

3 x (x + 2) = 6 (x - 3)

- 3 x^{2} - 48 x = 0

- 2 x^{2} + 7 x + 15 = 0

- 4.9 t^{2} + 18 t + 22 = 0

x^{2} + 3 \cdot (- 10) = 0

What are the solutions to the equation (-5)^2+(2)^2=D^2 ?
The solutions to the equation (-5)^2+(2)^2=D^2 are D=sqrt(29),D=-sqrt(29)
Find the zeros of (-5)^2+(2)^2=D^2
The zeros of (-5)^2+(2)^2=D^2 are D=sqrt(29),D=-sqrt(29)